$\frac{m}{5}=\frac{1}{5}m$

$-\frac{a}{4}=-\frac{1}{4}a$

$\frac{2x}{7}=\frac{2}{7}x$

$-\frac{5y}{8}=-\frac{5}{8}y$

$\frac{x-1}{3}=\frac{1}{3}(x-1)=\frac{1}{3}x-\frac{1}{3}$

$\frac{2x-3}{2}=\frac{1}{2}(2x-3)=x-\frac{3}{2}=x-1,5$

$\frac{x^2-3x}{10}=\frac{1}{10}(x^2-3x)=0,1x^2-0,3x$

$\frac{m^2-mn+n^2}{8}=\frac{1}{8}(m^2-mn+n^2)=\frac{1}{8}{m}^2-\frac{1}{8}mn+\frac{1}{8}{n}^2$

$\frac{(a-1)\ast 3}{5}=\frac{1}{5}(3a-3)=\frac{1}{5}\ast 3a-\frac{1}{5}\ast 3=\frac{3}{5}a-\frac{3}{5}$

$\frac{(p-q)(p+4)}{4}=\frac{1}{4}(p^2-pq+4p-4q)=\frac{1}{4}{p}^2-\frac{1}{4}pq+\frac{1}{4}\ast 4p-\frac{1}{4}\ast 4q=\frac{1}{4}{p}^2-\frac{1}{4}pq+p-q$